- What is the pressure in atmospheres of a gas mixture that consists of 8.80 grams of nitrogen and 8.80 grams of carbon dioxide in a 2.01 liter container at 27°C?

Select one:

a. 6.30 atm Correct

b. 3.85 atm

c. 2.45 atm

d. 0.971 atm

My calculations give an answer of 10.1 atm. Thanks in advance for any guidance correcting my calculations.

P=nRT/V ; **solve for pressure**

n=0.828 mol ; **convert to mol** 8.80g N * 1 mol/14.007g N = 0.628 mol N + 8.80 g CO2 * 1 mol/43.999 g CO2 = 0.200 mol CO2

R = 0.0821 L*atm/mol*K

T = 300 K ; **convert celsius to kelvin** 27 + 273.15

V = 2.01 L

P = (0.828 mol * 300 K * 0.0821 L * atm)/(2.01 L * mol * K)

P = 10.1 atm ; **rounded to 3 sig. digits**