- What is the pressure in atmospheres of a gas mixture that consists of 8.80 grams of nitrogen and 8.80 grams of carbon dioxide in a 2.01 liter container at 27°C?
a. 6.30 atm Correct
b. 3.85 atm
c. 2.45 atm
d. 0.971 atm
My calculations give an answer of 10.1 atm. Thanks in advance for any guidance correcting my calculations.
P=nRT/V ; solve for pressure
n=0.828 mol ; convert to mol 8.80g N * 1 mol/14.007g N = 0.628 mol N + 8.80 g CO2 * 1 mol/43.999 g CO2 = 0.200 mol CO2
R = 0.0821 L*atm/mol*K
T = 300 K ; convert celsius to kelvin 27 + 273.15
V = 2.01 L
P = (0.828 mol * 300 K * 0.0821 L * atm)/(2.01 L * mol * K)
P = 10.1 atm ; rounded to 3 sig. digits