Need help reasoning this out:

What is corresponding z’ for r=-.65?

z’ = 0.5 ln[(1+r)/(1-r)

The answer is supposed to be **-.775**, but I keep getting other answers. I am pretty sure the normal table is needed here

Need help reasoning this out:

What is corresponding z’ for r=-.65?

z’ = 0.5 ln[(1+r)/(1-r)

The answer is supposed to be **-.775**, but I keep getting other answers. I am pretty sure the normal table is needed here