Hi this is Sachin! I am a Student Success Coach and will be explaining some practice problems from the MA001 Algebra course. Today we will review an assigned problem from Unit 1. In the “Homework Assessment” you were asked to solve this problem:

We will use the “order of operations” principles to simplify this expression.

We will approach this problem as follows:

- Simplify the top.
- Simplify the bottom.
- Divide top by bottom.

**Step 1:** Simplify the top:

**a)** Simplify the exponent:

Therefore, the expression for the top becomes

8 + 4

**b)** Perform addition:

→ 8 + 4 = 12

Therefore, simplified top is 12.

**Step 2:** Simplify the bottom:

-18 - 6 + (-4) - [-5 (-1) (-5)]

**a)** Simplify the bracket -5 (-1) (-5)

**i)** Perform a multiplication from left to right, -5 (-1) = 5 therefore,

→ -5 (-1) (-5) = 5 (-5)

**ii)** Perform a multiplication

→ 5 (-5) = -25, this is simplified bracket term

Therefore, the bottom expression becomes

-18 - 6 + (-4) - [-25]

**b)** Eliminate parenthesis and bracket.

**i)** A positive multiply to negative number is a negative number +(-4) = -4

→ -18 - 6 - 4 - [-25]

**ii)** A negative number multiplied to negative number is a positive number.

→ -18 - 6 - 4 + 25

**c)** Perform the arithmetic operations:

**i)** Perform subtraction from left to right: -18 - 6 = -24

→ - 24 - 4 + 25

**ii)** Perform subtraction from left to right: - 24 - 4 = - 28

→ - 28 + 25

**iii)** Perform the addition:

→ - 28 + 25 = - 3

Therefore, the simplified bottom is - 3.

**Step 3:** Divide the simplified top by simplified bottom, and simplify the fraction:

**a)** Simplified top is 12, and simplified bottom is -3.

Therefore, the fraction is

b) Simplify this fraction:

**Conclusion:**

By using the order of operation, the solution for the given expression

is -4.

In addition to this, I am also attaching the pdf document of the practice problem for your ready reference.

Question 23.pdf (229.8 KB)

Please let me know if you have any question on this problem, or ‘Order of Operations’ generally. I will be here in the forum for the next hour.